Re: In app provisioning . authcode

Jheank16oz
Regular Visitor

In app provisioning . authcode

Hi,

I'm integrating In-app provisioning Apple Pay, could you please tell me how is generated authcode within 

encryptedinformation value.

 

 
4 REPLIES 4
API_Managers
Visa Developer Support Specialist

Re: In app provisioning . authcode

Hey @Jheank16oz,

 

Can you please confirm the API that you are using to integrate the in-app provisioning Apple Pay? Are you using Visa Token Service? 

 




Thanks,

Tee



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Jheank16oz
Regular Visitor

Re: In app provisioning . authcode

Actually any API, I'm just creating activation-data and authentication data from a host. It is the mobile flow when the card is added from banking app, not from the wallet.
API_Managers
Visa Developer Support Specialist

Re: In app provisioning . authcode

Hey @Jheank16oz,

 

I'll take a look and get back to you soon.

 

 




Thanks,

Tee



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API_Managers
Visa Developer Support Specialist

Re: In app provisioning . authcode

Hey @Jheank16oz,

 

After further review of your questions, we are not quite sure what you are asking for.

You said, "Actually any API, I'm just creating activation-data and authentication data from a host. It is the mobile flow when the card is added from banking app, not from the wallet. "

The Authorization code usually comes from the issuing bank, after an authorization.

The encrypted payment data usually is the blob or envelope that sends the payment information from the wallet to the merchant, and therefore wouldn't have an authorization code.

Provisioning is when the token is created and the reference number is passed back to the wallet.
Is you suggesting you would authorize the card first and then attempt to provision using our Visa Token Service API? Can you please provide the documentation to which you are referring to?

As always, Visa Token Service is an exclusive program, and this might be best directed to the integrator that you are utilizing, that way your integrator can inform you on on how the product functions.

 




Thanks,

Tee



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